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1/x=256^x
We move all terms to the left:
1/x-(256^x)=0
Domain of the equation: x!=0We multiply all the terms by the denominator
x∈R
-256^x*x+1=0
Wy multiply elements
-256x^2+1=0
a = -256; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-256)·1
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32}{2*-256}=\frac{-32}{-512} =1/16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32}{2*-256}=\frac{32}{-512} =-1/16 $
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